What conclusion can be drawn if Rocket A weighs twice as much as Rocket B and both are descending at the same speed?

Kinetic energy is defined by the formula ( KE = \frac{1}{2}mv^2 ), where ( m ) is mass and ( v ) is velocity. If Rocket A weighs twice as much as Rocket B, then its mass can be expressed as ( 2m ) (where ( m ) is the mass of Rocket B). Both rockets are mentioned to be descending at the same speed, meaning their velocities ( v ) are equal.

When calculating the kinetic energy for both rockets using the formula:

• For Rocket A:

[

KE_A = \frac{1}{2}(2m)v^2 = mv^2

]

• For Rocket B:

[

KE_B = \frac{1}{2}mv^2

]

Now, by comparing the kinetic energies, it is evident that:

[

KE_A = 2 \times \left( \frac{1}{2}mv^2 \right) = 2 \times KE_B

]

This shows that Rocket A, having twice the mass of Rocket B and moving at the same velocity, has twice the kinetic energy of Rocket B. This demonstration aligns with